Twenty-seven is
% of 60
mee asap

 The answer is:  " 45  % "  .    

               →    " Twenty-seven is 45 % of 60. "

Step-by-step explanation:

The question asks:

 " 27 is what % {percentage] of 60 " ?  ;

So:  " 27 =  (n/100) * 60 " ;  Solve for "n" ;

Method 1:

  →   (n/100) * 60 = 27 ;

Divide each side by 60 :

 →   [ (n/100)  * 60 ] / 60 = 27 /60 ;

to get:

 →    (n/100) = 27/60 ;

Now:  Cross-factor multiply:

 →  60n = (27)*(100) ;

to get:

 → 60n = 2700 ;

Divide each side by "60" ;

→  60n = 2700/ 60 ;

to get:  n = 45 ;

 →  The answer is:  45 % .    

   →  " Twenty-seven is 45 % of 60."

Method 2:

The question asks:

 " 27 is what % {percentage] of 60 " ?

To solve this problem:

Rephrase this question as:

" 27 is 60% of what number ? "

 →  The answer will be the same!

→  27 = (60/100)* n ;   Solve for "n" ;

Multiply each side of the equation by "100" ; to eliminate the fraction:

→  100 * 27 = 100 * [ (60/100)* n ] ;

 to get:

   →   2700 = 60n ;

↔  60n = 2700 ;

Divide Each Side of the equation by "60" ;

    →   60n/60 = 2700 / 60 ;

to get:  n = 45 ;

→  The answer is:  45 % .    

       →  " Twenty-seven is 45 % of 60."

Method 2:  Variant 1 of 2:

When we have:

→  27 = (60/100)* n ;   Solve for "n" ;

Note that:  "(60/100) = (60÷ 100) = (6 ÷ 10)" ;   since:  in "(60/100)" ;  the "zero" from the "numerator" cancels out;  And:  the "last zero" in "100" — from the "denominator" cancels out;  since we are dividing "each side" of the fraction by "10" ;

  →   "(60÷10) / (600÷10)"  =  " 6/10 " ;  

  →   " (6/10)" ; that is;  "six-tenths"} ;  

  →     can be represented by:  " 0.6 " ;

  →  {by convention;  but specifically, here is the explanation} — as follows:

  →   "(6/10)" =  " (6 ÷ 10) " ;  

Note:  When dividing a number by "10" ;  we take the original number; and move the decimal point to the left; & then we rewrite that number as the "answer".  

Note:  When multiplying or dividing by a positive, non-zero integer factor of "10" that has at least 1 (one) "zero" after that particular factor of "10".  We can get the answer by taking the original number & moving the decimal point the number of spaces as designated by the number of zeros following the particular [aforementioned factor of "10".].

We move the decimal point to the right if we are multiplying;  and to the left  if we are dividing.  In this case, we are dividing "6" by "10 " :

 →  " 6   ÷  10  =  ? " ;  

 →  " 6.  ÷ 10 =  ? " ;

   We take the: " 6. " ;  and move the decimal point "one space backward [i.e. "to the left"];  since we are dividing by "10" ;

 →  to get:  " .6 " ;  & we rewrite this value as "0.6" in a rewritten equation:

So; we take our equation:

→  27 = (60/100)*n ;  And rewrite—substituting "0.6" for

"(60/100)"— as follows:

→  27 = (0.6)n ;  ↔ (0.6) n = 27 ;

Multiply each side of the equation by "10" ; to eliminate the decimal:

   →  10 * [ (0.6)n ]  = 27 * 10 ;

to get:

  →  6n = 270 ;

Divide each side of the equation by "6" ; to isolate "n" on one side of the equation; & to solve for "n" ;

 →  6n / 6  =  270 / 6 ;

to get:   n = 45 ;

→  The answer is:  45 % .    

      →  " Twenty-seven is 45 % of 60."

Method 2 (variant 2 of 2):

We have the equation:  27 = (60/100)* n ;   Solve for "n" ;

Note:  From Method 2 (variant) 1 of 2— see above):

Note:  Refer to the point at which we have:

→   " {  (60÷10) / (600÷10)"  =  " (6/10) " ;  that is;  "six-tenths"} ;

Note that the fraction— "(6/10)" ;  can be further simplified:

→  "(6/10)" =  "(6÷2) / (10÷2)" = "(3/5)" ;

Now, we can rewrite the equation;

→ We replace "(60/100)" ;  with:  "(3/5)" :

    →  27 = (3/5)* n ;   Solve for "n" ;

↔ (3/5)* n = 27 ;  

↔    (3n/5) = 27 ;

Multiply Each Side of the equation by "5" ;

→  5* (3n/5) = 27 * 5 ;  

to get:

→   3n = 135 ;

Divide Each side of the equation by "3" ;  to isolate "n" on one side of the equation;  & to solve for "n" ;

→  3n / 3 = 135 / 3  ;

to get:   n = 45 ;

 →  The answer is:  45 % .    

       →  " Twenty-seven is 45 % of 60."

Hope this answer is helpful!

        Wishing you the best in your academic endeavors

           — and within the "" community!

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah