Correct answers only ! if you don't know the answer, then don't guess or say what you think it is.
mike recently increased the size of his truck tires from the original p215/60r16 to the larger p235/7016. if mike didn't recalibrate his speedometer, how fast is really going on the new tires when his speedometer shows he is traveling 60 mph?
a. 54.2 mph
b. 63.8 mph
c. 66.4 mph
d. 69.7 mph

B

Step-by-step explanation:

P215/60R16 meaning

215 is width in millimeters

60 is the ratio of the height of the tire’s cross-section to its width

16 is wheel diameter

So rim height is

60*215/100 = 129 mm = 5 inches

Then, total diameter of tyre is

16'' + 5'' = 21''

that means radius is 21''/2 = 10.5''

The new tyre P235/70R16 have a height of

70*235/100 = 164.5 mm = 6.5''

and its total diameter is

16'' + 6.5'' = 22.5''

that means radius is 22.5''/2 = 11.25''

We know that linear velocity (v) is the radius (r) times the angular velocity (). For the first case

And for the second one

Angular velocity doesn't change from the first case to the second case, i. e., . Combining the equations and replacing with values give

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4