Collinear line segment , pt = 20, qs = 6 ,
pq = qr = rs
what’s the length of qr, rs, pq, st, rp, rt, sp, and qt?

as p, q, r, s, t  

given pt = 20

pq=qr = rs  

with qs = 6

so qr = rs = 3

pq = 3

st = 11

rt =14

sp =9

rp =6

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet