How can i do this equation 8y-(5y+2)=16

Hey!

Solution:

8y - (5y + 2) = 16

3y - 2 = 16

3y + (-2) + 2 = 16 + 2

3y = 18

3y/3 = 18/3

y = 6

y = 6

Hope This Helped! Good Luck!

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."