r^2=16/cos2theta
Mathematics, 09.09.2019 08:10 sandyykn192
Convert the cartesian equation x ^2 + y ^2 - 4x = 0 to a polar equation.
r^2=16/cos2theta
r=-4
r^2=8
Answers: 2
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Convert the cartesian equation x ^2 + y ^2 - 4x = 0 to a polar equation.
r^2=16/cos2theta
r^2=16/cos2theta
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