Asmall software corporation borrowed $ 250,(000) to expand its software line. the corporation borrowed some of the money at 9%, some at 10%, and some at 12%. use a system of equations to determine how much was borrowed at each rate if the annual interest rate was $26,000 and the amount borrowed at 10% was 2.5 times the amount borrowed at 9%.

$50,000 was borrowed at 9%.

$125,000 was borrowed at 10%.

$75,000 was borrowed at 12%.

Step-by-step explanation:

Let amount borrowed at 9% be x

Let amount borrowed at 10% be y

Let amount borrowed at 12% be z

Now equations form:

     ....(1)

    ....(2)

  ..... (3)

Substituting the value of y from (3) in (1) and (2)

=>   ......(4)

=>   ....(5)

Multiplying (4) by 0.12 and subtracting (5) from it, we get

-

0.08x=4000

x = $50000

As y = 2.5x

So,

y = $125000

And as x+y+z=250000

=>

z = $75000

Therefore, $50,000 was borrowed at 9%.

$125,000 was borrowed at 10%.

$75,000 was borrowed at 12%.

answer: b.

step-by-step explanation:

it is b. cause the equations are put in the right category

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this