Which interval contains a local minimum for the graphed
function?
of-4, -2,51
o [-2, -1]
o [1, 2]
o [2.5, 4]

The interval which contains the local minimum is [2.5 , 4] ⇒ last answer

Step-by-step explanation:

"I have added screenshot of the complete question as well as the diagram"

- From the graph of the function there are two local minimum points

- Point (-0.44 , -4.3) and point (3 , -4)

- At the the minimum local points the differentiation of the function

  equal to zero

- If the the name of the function on the graph is h(x)

∵ h'(x) = 0 gives two values of x, one of them is -0.44 and the other is 3

∴ h'(-0.44) = 0

∴ h'(3) = 0

- The interval which contains the local minimum must has on of

  these two values -0.44 and 3

∵ x = -0.44 is between -1 and 0

∴ The interval [-4 , -2.5] does not contain local minimum

∴ The interval [-2 , -1] does not contain the local minimum

∵ x = 3 is between 2 and 4

∴ The interval [1 , 2] does not contain the local minimum

∴ The interval [2.5 , 4] contains the local minimum

* The interval which contains the local minimum is [2.5 , 4]

reduce the friction between its moving parts

step-by-step explanation:

in fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).