Verify that quadrilateral bcde is a rhombus with vertices b(5, -1), c(-2, 0), d( -1, 7) and e(6, 6) by showing that all four sides are equal.
a. bd = ce = √50
b. bd = ce = 50
c. bc = cd = de = eb = 50
d. bc = cd = de = eb = √50

The right answer to your question is: D = √50

Step-by-step explanation:

We need to use the formula of distance between to points

  √(x2-x1)² - (y2-y1)²      

√(-2-5)² +(0+1)² = √50       =     √ (-7)² + (1)² = √49 + 1

 √(-1+2)² + (7-0)² = √50       =     √ 1² + 7²   =   √1 + 49 = √50

 √(6+1)² + (6-7)² = √50

√(6-5)² + (6+1)² = √50

89

step-by-step explanation: