Instructions: factor 715 as a product of primes.
input the number's prime factors in ascending
order.
first factor:
second factor:
third factor:

{1, 5, 143}

Step-by-step explanation:

715 is evenly divisible by 5, so one factor of 715 is 5 and the next is 715/5, or 143.  143 is not factorable further.  Thus, the factors of 715, in ascending order, are 1, 5 and 143.

which expression represents the approximate length of bc?

step-by-step explanation:

ummm seems that u didnt post the attachement !