Suppose g is the function g(x) = 2^x and g : {1, 2, 3} -> {1, 2, 4, 8}
is g one-to-one:
is g onto:

Step-by-step explanation:

Given that g is a function from g : {1, 2, 3} ->{1, 2, 4, 8}

by the function

i.e. we have

Range = {2,4,8} Since there is an extra element 1 in the co domain which is not in range , g is not on to

But g is one to one as 1,2,3 have different images.

x = 25/2304

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)