Which shows the correct substitution of the values a, b, and c from the equation 0 = 4x2 + 2x - 1 into the quadratic formula
below?
quadratic formula: x = -by
2a
x= -2=22 - 4(4)(– 1)
2(4)
x=-2/22 - 4(4)(1)
2(4)
y=-2/22 +4(4)( - 1)
2(4)
-2 +/-2² – 4(4) (-1)
2(4)

pooopoopopoopop

step-by-step explanati∵∵∴∴on:

5y

step-by-step explanation:

a

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)