One of the equilateral triangular faces of a regular square pyramid is glued to a triangular face of a congruent regular square pyramid. if the side length of the regular square pyramid is 8, find the surface area of the new solid.

128 + 96√3 or 294.28 unit^3 to the nearest hundredth.

Step-by-step explanation:

The surface area of one of the pyramids = area of the square base + area of the 4 equilateral triangles

=  8^2 +  4 * 1/2 * 8 * 4√3

= 64 + 64√3.

So the area of the new solid =  2(64 + 64√3) - area of 2 triangles

=  2(64 + 64√3) - 32√3

= 128 + 128√3 - 32√3

= 128 + 96√3.

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

step by step explanation: when u removing the parentheses and combined them that would be : x+3y-x-y=2y