The current in a circuit element is i(t) = 3(1 - e-2t) a when t ≥ 0 and i(t) = 0 when t < 0. the total charge that has entered the circuit element for t ≥ 0 can be represented as q left-parenthesis t right-parenthesis equals upper a ⁢ plus upper b t plus upper c e superscript negative a t coulomb, where a, b, c and a are real constants. determine the values of a, b, c and a.

A=-3/2

B=3

c=3/2

a=-2

Step-by-step explanation:

Knowing that for , when t<0 and using the definition of charge

The first term corresponds to q(0), the charge accumulated before t=0, in this case it luckily gives zero so we don't have to worry about it.

Let's proceed and integrate then when t>0

It is clear that:

A=-3/2

B=3

c=3/2

a=-2

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

idk

step-by-step explanation: