Answers: 3
with initial condition 
. We have,
, hence we can say that 
and 
in the general form of the first order linear differential equation:
. Thus, multiplying the entire equation by the integrating factor:
. This means that:![\frac{d[e^{3x}y]}{dx} = 24e^{3x}](/tpl/images/0224/4674/9350f.png)
then
. Applying the initial condition:
and therefore, 
with initial condition 
, hence we can say that 
and 
in the general form of the first order linear differential equation:
. Thus, multiplying the entire equation by the integrating factor:
. This means that:![\frac{d[e^{\frac{x}{3}}y]}{dx} = 8e^{\frac{x}{3}}](/tpl/images/0224/4674/541b4.png)
then
. Applying the initial condition:
and therefore, 
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Solve the initial-value problem y = 24 – 3yy(1) = 1....
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