The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. the distribution of the number of daily requests is bell-shaped and has a mean of 39 and a standard deviation of 3. using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 39 and 48?
do not enter the percent symbol.
ans = %

50 percent

Step-by-step explanation:

Mean = 39

Using the 68-95-99.7 rule, 68% of the data falls within first  standard deviation of mean

95% data falls within two standard deviation of mean

99.7% data falls within 3 standard deviation of mean

Refer the attached graph

The curve is normally distributed

Now the the percentage of light bulb replacement requests numbering between 39 and 48 = 34%+13.5%+2.5% = 50%

Hence  the approximate percentage of light bulb replacement requests numbering between 39 and 48 is 50 .

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

chiken

step-by-step explanation: