The square of a number is equal to 10 less than 7 times that number. what are the two possible solutions?
which of the following equations is used in the process of solving this problem?
x^2 - 7x + 70 = 0
x^2 - 7x + 10 = 0
x^2 + 7x - 10 = 0

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x