The ratio of losses to wins for kyle's team is 3 to 2. if the team had played the same number of games, but had won twice as many of its games, what would the ratio of losses to wins have been? express your answer as a common fraction.

The new ratio will be 1/4

Explanation: The initial ratio of losses to wins is 3 to 2. If we sum the numer of losses and wins 3 + 2 = 5 games, that means they loss 3 out of 5 games , and they win 2 out of 5 games.

So if they had won twice as many of the games, that is 2*2=4. And since the number of games is the same ( 5 ), then they would have won 4 games and loss only 1.

So the new ratio of losses to wins will be 1 to 4, or expressed in a fraction: 1/4

the ratio would ben 1 to 4, or (1/4) as a common fraction, this means that the number of games that the team lost is equal to 1/4 of the games that the team won.

Step-by-step explanation:

the ratio is 3 to 2

this means that if they played 5 games (because 3 + 2 = 5), 3 of those games were losses and 2 where wins.

Now, if they played the same number of games (5) and won twice as many of the games (2) them would have wined 2*2 = 4 of 5 games.

then the rate of loses to wins is:

1 to 4

this means that they lost 1 game for every 4 wins.

y=mx+

56

step-by-step explanation: