In a shipment of 54 vials, only 15 do not have hairline cracks. if you randomly select 3 vials from the shipment, what is the probability that none of the 3 vials have hairline cracks?

1.83%

Step-by-step explanation: From 54 vials

15 do not have cracks

39 have cracks

selecting 3 randomly, NONE having cracks:

For the 1st option, 15 out of 54 do not have cracks

For the 2nd option, 14 out of 53 do not have cracks, because you are not going to take the same one.

For the 3rd option, 13 out of 52 do not have cracks, because you are not going to take the same one.

15/54 . 14/53 . 13/52 = 2730/148824 = 0.0183 = 1.83%

answer: (1,3) and (-2,0) i think.

10000

step-by-step explanation: divide by 2,