Hey guys me anyone i mean anyone whoo explains well and not for the points will be marked as brainliest .solve each system by substitution so we have -4x+6y=12
x+2y=-10 so far i got -14y=52 dont get me wong i know how to solve it but since 14 goes into 52 3 times do i then have to plug in for y

-4x + 6y = 12
x + 2y = -10

First solve for x in the second equation

x + 2y = -10
x = -10 - 2y

Now we have a value for x so we can substitute it into the other equation

-4 (-10 - 2y) + 6y = 12

Now solve for y

40 + 8y + 6y = 12
40 + 14y = 12
14y = -28
y = -2

Now we have a value for y that we can plug into one of the original equations so we can solve for x

x + 2y = -10
x + 2(-2) = -10
x - 4 = -10
x = -6

Your solution set is

(-6, -2)