The length of a rectangle is 6cm longer than the width. if the length is increased by 9cm and the width by 5cm, the perimeter will be 160cm. find the dimensions of the original rectangle.

Step-by-step explanation:

Let w represent the width of the original rectangle in cm. Then its length is (w+6). The dimensions of the increased rectangle are ...

And the total of these new values is half the perimeter: 80.

  (w +15) +(w +5) = 80

 2w = 60 . . . . . . . . . . . . . subtract 20, collect terms

  w = 30 . . . . . . . . . . . . . . divide by 2

The dimensions of the original rectangle are ...

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.