Find an equation of the line passing through the point (-4,6) that is perpendicular to the line y=7/2x+5. work .

y = x + 4

Step-by-step explanation:

We are to find the equation of line 1 which passes through point (-4,6)

Line 1 is perpendicular to line 2.

The equation of line 2 is; y = x + 5

The slope of line 2 is  

Because the product of two perpendicular line is -1;

The slope of line 1 is -1 ÷   =  

Taking another point (x,y) on line 1;

Slope = change in y ÷ change in x

=

y - 6 =  (x + 4)

y - 6 =  x -

y =   - + 6

y = x + 4

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

answer: your answer is c

step-by-step explanation: