There is a class of 63 students. the teacher and each student owns and keeps in his/her pocket a working cell phone. each of these cell phones has a log of the phone number of everyother student. email is down. the teacher will cancel class and needs to let the class know as fast as possible since the class starts in 15 minutes. clearly, the teacher can't call all the students himself; there isn't enough time. write an algorithm for the teacher to follow to expedite informing all students in the class that it is cancelled. note: you are to assume that you are living in 1999 when there was no text messaging and no conference calling, i. e. you can only make one call to one recipient at a time and each call takes exactly 2 minutes.

answer: what is the question you're trying to ask?

step-by-step explanation:

a

step-by-step explanation:

answer: h=5.6 i don't really know how to put into words, so i though i would let you do that. i hope i was able to some

step-by-step explanation:

18 = 6(h)+1/2

18 = 6h+1/2

18-1 = 6h/2

17 = 3h

17/3 = h

h = 5.6

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)