Find an equation of the line perpendicular to the graph of 14x-7y=8 that passing through the point at (-2,5)

For this case we have to by definition, if two lines are perpendicular then the product of its slopes is -1.

We have the following line:

Rewriting:

Thus, the slope is:

We have to:

(Perpendicular condition)

Thus, the equation of the line is:

We find "b" knowing that the line passes through the point (-2,5).

Finally, the equation is:

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8  

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.