What is the solution of this system of linear equations? 3y = 3 y equals startfraction 3 over 2 endfraction x plus 6.x + 6 y – startfraction one-half endfraction y minus startfraction 1 over 4 endfraction x equals 3.x = 3 (3, 6) (2, 1) no solution infinite number of solutions

(0,6)

Step-by-step explanation:

The given system of equations is

and

We substitute the first equation into the second equation to get:

We expand to get:

We group similar terms to get:

Put x=0 in to the first equation to get:

Therefore the solution is (0,6)

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.