Estimating sample size using military significant difference. suppose we are buying a new system that is designed to have an infrared detection range of 14.0 km or more. if the actual infrared detection range is less than 11.5 km, the effectiveness of the system would not support mission requirements. during testing we are willing to accept a probability of type 1 error (alpha) of 0.05, but we want to have a 0.975 probability of detecting a "bad" system. prior test results indicate that the standard deviation of the detection range is normally distributed and should be about 2.8 km. how many trials do you estimate will be required to meet this criteria?

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

r and t.

both are 64 degrees.