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Mathematics, 03.09.2019 10:10 BookandScienceNerd

Me check my answers for these problems
guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal places)
numbers given: -2.5,-2.9,-2.95,-2.99,-2.999,-2.
-3.5,-3.1,-3.01,-3.001,-3.0001
lim (x--> -3)
\frac{x^2-3}{x^2-9}
determine the infinite limit
1)
lim (x--> 5^+)
\frac{x+1}{x-5}
2)
lim (x--> 1)
\frac{2-x}{(x-1)^2}

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Answers: 2

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