Three consecutive integers are such that three times the smaller is fourteen more than the largest. find the integers

8, 9, 10

Step-by-step explanation:

Let the three consecutive numbers be;

First number = a

Second number = a + 1

Third number = a + 2

Three times the smaller number is fourteen more than the largest.

i.e 3a = (a + 2) + 14

3a = a + 16

3a - a = 16

2a = 16

a = 16 ÷ 2 = 8

So the first number is 8 and the next two consecutive numbers are 9 and 10.

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.