In 2010, car a was the highest mileage car available in a country. it's estimated highway mileage was 4 miles per gallon more than car b . if the two cars could travel a total of 90 miles on a gallon of gasoline, find the mileage of each car.

Car B = 43 miles per gallon

Car A = 43+4=47 miles per gallons

Step-by-step explanation:

Let the mileage of Car B be x miles per gallon

Hence the mileage of Car A will be x+4 miles per gallon

Distance traveled by each car in 1 gallon

Car A = x+4

Car B = x

Total Distance covered by both car in 1 gallon = x+(x+4) which is given as 90 miles

Hence x+(x+4)=90

2x+4=90

2x=86

dividing both sides by 2 we get

x=43

Mileage of Car B = 43 miles per gallon

Mileage of Car A = 43+4=47 miles per gallons

step-by-step explanation:

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!