Afirm works 7 days a week. every employee must work exactly 3 full days and 4 half-days each week. a half-day can be either morning or afternoon, and two half-days cannot be held on the same day. a) how many possible different weekly schedules are there? 560 expected 560

  a)  560 (as you know)

Step-by-step explanation:

There are 7C3 = 35 ways to choose 3 full-time days from 7.

There are 2^4 = 16 ways to choose a half-day each day from the remaining 4 days.

The total number of possible schedules is ...

  35×16 = 560

nCk = n!/(k!(n-k)!)

7C3 = 7·6·5/(3·2·1) = 7·5 = 35

the answer to this question is in the pic

the answer is b. 60. each interior angle in 120, so the exterior angle must be 60 in order to add up to 180

step-by-step explanation: