Of the three-digit positive integers whose three digits are all different and nonzero, how many are odd integers greater than 700 ?

91

Step-by-step explanation:

Given that there are three digit positive integers whose  three digits are all different and nonzero

Since it is given as odd integers and greater than 700,

we have the numbers of the form

with first digit >6, last digit any one of 1,3,5,7,9 alone

Thus we can select first digit in 4 ways.

If first digit is 7, then unit digit has only 4 choices excluding 7, and second digit 7 ways.  Thus starting with 7 = 28 numbers

Starting with 8:

Unit digit can be any one of the five odd, and second digit 7 ways

No of digits = 35

Similarly for 9, we get 28.

Hence total numbers that can be formed that are odd and >700 are

ans789

step-by-step explanation:

step-by-step explanation: