Write the equation of the line that passes through (3, −2) and has a slope of 4 in point-slope form. (2 points)
a
y + 2 = 4(x − 3)
b
y − 3 = 4(x + 2)
c
x − 3 = 4(y + 2)
d
x + 2 = 4(y − 3)

A. y+2=4(x-3)

Step-by-step explanation:

To write an equation in slope-point form you write as;

y-y₁=m(x-x₁) where m is slope of line and (x₁,y₁) is one point on the line

In this question you are given m=4 and (x₁,y₁) as (3,-2) then the equation is

y-y₁=m(x-x₁)substitute values

y--2=4(x-3)simplify further

y+2=4(x-3)

3=log(n)=2

answer a: product property

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1