Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5). write the equation of this cubic polynomial function. recall that the zeroes are (2, 0), (3, 0), and (5, 0). what is the y-intercept of this graph?
–5
–2
3
5

Equation of the polynomial function is

The y-intercept is -5

Step-by-step explanation:

According to the Descarte's theorem , a polynomial p(x) that has a zero r, that is p(r)=0, then it follows (x-r) is a factor of p.

If f(x) has zeros 2,3 and 5 then f(x) has factors (x-2),(x-3) and (x-5) hence to find the equation

f(x)=a(x-2)(x-3)(x-5)

f(x)={a(x-2)(x-3)(x-5)}-----------------------expand

f(x)={a (x(x-3)-2(x-3)⇒x²-3x-2x+6⇒x²-5x+6

f(x)={a (x²-5x+6)(x-5)}

f(x)={a x(x²-5x+6)-5(x²-5x+6)}

f(x)=a(x³-5x²+6x-5x²+25x-30)

Given that we have one hang point (0,-5), let x=0, f(x)=-5 find a

-5=a(0-0+0-30)

-5=-30a

a=-5/-30

a=1/6

Equation⇒ f(x)=1/6 (x³-10x²+31x-30)

To get y-intercept plugin x=0 in the equation , you notice the value of the function will be -5, hence y-intercept is -5

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people