The population sizes of many animal species rise and fall over time. suppose that the population size of a certain species can be modeled by the following. p (0) = 4005 â 1158 cos (274) in this equation, pt) represents the total population size and t is the time in years). suppose we start at t=0 years. during the first 9 years, when will the population size be 4800? do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a year. (if there is more than one answer, enter additional answers with the "or" button.) t = years x 6 ?

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles

the answer is 48m^2!

step-by-step explanation:

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.

if im not mistaking its

step-by-step explanation: