Frank has a sheet of paper which is 1/624 inch thick. if the sheet is folded in half, the total thickness will be 1/312 inch a second fold will produce a total thickness of 1/156 inch. what will be the thickness of the sheet if frank folds it 8 times?

The thickness of the sheet will be 16/39 inch after folded 8 times

Step-by-step explanation:

* Lets explain how to solve the problem

- Frank has a sheet of paper of 1/624 inch thick

- The sheet is folded in half, the total thickness is 1/312 inch

- The sheet folded in half again and the total thickness is 1/156 inch

- We need to know the thickness of the sheet after folded 8 times

∵ The 1st thickness is 1/624 inches

∵ The 2nd thickness is 1/312 inch ⇒ after 1st fold

∵ The 3rd thickness is 1/156 inch⇒ after 2nd fold

∵ 1/312 ÷ 1/624 = 2

∵ 1/156 ÷ 1/312 = 2

∴ There is a common ratio 2 between each two fold

∴ The thicknesses of the sheet after each fold formed a

   geometric series

∵ Any term of the geometric series is , where

  a is the first term, r is the ratio between each two consecutive

  terms and n is the position of the term

∵ a = 1/312 because it is the thickness of the 1st fold

∵ r = 2 , n = 8

∴

∴ The thickness of the sheet will be 16/39 inch after fold 8 times

14

step-by-step explanation:

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3