How many grams of nacl are required to prepare 60ml of a 19% solution

There is 11.40 grams of NaCl  are required to prepare the solution

Step-by-step explanation:

* Lets explain how to solve the problem

- We want to prepare 60 mL of 19% solution of NaCl

- The concentration of NaCl is 19%

- The volume of solution is 60 mL

- We need to find the mass of NaCl

- We must to understand the meaning of concentration %  

- Concentration % means x grams of solute in 100 mL of solution

- So, 19% of NaCl means 19 grams of NaCl in 100 mL of solution.

∵ In 100 mL of solution, we need 19 grams of NaCl

∴ Find how many gram in 60 mL by using cross multiplication

∵ 19 grams ⇒ 100 mL

   x grams ⇒ 60 mL

- By using cross multiplication

∴ x × 100 = 19 × 60

∴ 100 x = 1140

- Divide both sides by 100

∴ x = 11.40

∵ x represents the NaCl grams in the solution

∴ There is 11.40 grams of NaCl  are required to prepare the solution

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -