Solve the system of equations using substitution. y = β2x + 1 4x + 2y = β2
no solution
...
Mathematics, 30.08.2019 21:30 hopkinbr
Solve the system of equations using substitution. y = β2x + 1 4x + 2y = β2
no solution
infinitely many solutions
(0, β4)
(β4, 0)
Answers: 1
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