Consider the following conditional statement.
if a + 1 = b, then b > a.
a. create a pair of values for a and b in which the numerical relationship shown in the given conditional statement is true. in your final answer, include the values of the variables and proof of truth.
b. is it possible to create a pair of values for a and b in which the numerical relationship shown in the given conditional statement is false? use complete sentences to explain your answer.

Step-by-step explanation:

Part A:

Lets take the value of a=10

Thus a+1=b

10+1=11 , it means the value of b is 11

11>10 or b>a

Now take the value of a as -3

Therefore a+1=b

-3+1= -2

-2>-3 or b>a

The pair of values for a and b are: a=10 then the value of b would be 11;

And a=-3; then the value of b would be: -2.

Part B:

It is not possible to create a pair of values for a and be, in which the numerical relationship shown in the given conditional statement is false, therefore b>a if a+1=b

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation:

30005

yes ok