Solve the initial-value problem
y cos x y' = (cosx)3 sinx, y(0) = −1.
note: the cosx is raised to a power of 3: (cosx)^3

Step-by-step explanation:

Given that

y(0)= -1

The above equation is a differential equation

So now by separating variables

We know that

So

Now by taking integration both side

Now by using y(0)= -1