The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals startfraction one-fourth endfraction left-parenthesis x minus 12 right-parenthesis.(x – 12). what is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2

The equation of the line in standard form is

Step-by-step explanation:

The equation of the line in point slope form is

we have

so

step 2

Find the equation of the line in standard form

The equation of the line in standard form is

where

A is positive integer

B and C are integers

we have

Multiply by 4 both sides to remove the fraction

the radius is 2 times the diameter.

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: