Consider the set a = {a, (b), c). what is the power set of a? o{0, {a}, {a,{b}}, {{b}}, {c, a}, {{b},c}, {c}, {a,{b},c}} o{0, {a}, {b}, {c}, {a, b}, {a, c}, {b, c}, {a, b,c}} o{0, {a}, {a,{b}}, {{b}}, {a, b,c}, {{b},c}, {c}, {a,{b},c}} o{0, a, b, c, {a, b}, {a, c}, {b, c}, {a, b,c}}

O{{}, {a}, {{b}}, {c}, {a,{b}}, {a,c}, {{b},c}, {a,{b},c}}.

Step-by-step explanation:

You have the following set:

A = {a, {b},c}

The power set of any set A is the set that contains all the subsets of A.

Each set B is a subset of A if B is contained in A.

Each N-cardinality set will have a -cardinality power set.

The subsets of A are:

- The empty set(The empty set is a subset of any set)

- Each element of A. So {a}, {{b}}, {c} are all subsets of A.

- Every combination between elements of A are subsets of A. So {a,{b}}, {a,c}, {{b},c} and {a,{b},c} are all subsets of A.

So the power set of A is

O{{}, {a}, {{b}}, {c}, {a,{b}}, {a,c}, {{b},c}, {a,{b},c}}.

-8

step-by-step explanation:

linear pair postulates