In a family of 10 children, where both parents are heterozygous for albinism, what mathematical equation predicts the probability that 8 are normal and 2 are albino?

In a cross between two heterozygous parents, the probability that a child is homozygous for albinism is 1/4. So out of 10 children, the probability that 8 are normal and 2 are albino is

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1