If ray jg is an angle bisector of ∠fjh, find m∠fjh.
m∠fjh = 15°
m∠fjh = 30°
m∠fjh = 45°
m∠fjh = 60°

m∠FJH=60°

Step-by-step explanation:

The complete question is

JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)°  

What is FJH

we know that

m∠FJH=m∠FJG+m∠GJH > equation A

If ray JG is an angle bisector of ∠FJH

then

m∠FJG=m∠GJH > equation B

substitute the given values in equation B and solve for x

(2x + 4)°=(3x -9)°

3x-2x=4+9

x=13

Find the measure of angle FJH

m∠FJH=(2x + 4)°+(3x -9)°

substitute the value of x

m∠FJH=(2(13) + 4)°+(3(13) -9)°

m∠FJH=(30)°+(30)°

m∠FJH=60°

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

what are ur choices?