"given: in ∆abc, segment de is parallel to segment ac .. prove: bd over ba equals be over bc. the two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally.. statement. reason. 1. segment de is parallel to segment ac. 1. given. 2. line segment ba is a transversal that intersects two parallel lines. 2. conclusion from statement 1. 3.. 3.. 4. ∡bde ≅ ∡bac. 4. reflexive property of equality. 5. ∆abc ~ ∆dbe. 5. angle-angle (aa) similarity postulate. 6.. 6.. "

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

its an acute right triangle

step-by-step explanation:

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: