What are the x-intercepts of the parabola?
graph of parabola falling from the left, passing through negative 6 comma 2 to about negative 4 and one half comma negative one fourth, and rising to the right, passing through negative 3 comma 2
(−5, 0) and (−4, 0)
(−4.5, 0) and (−4, 0)
(0, −4) and (0, −5)
(0, −4.5) and (0, −4)

A

Step-by-step explanation:

The x-intercepts of a parabola are where the parabola intersects the x-axis on its graph. There are a number of ways to find the x-intercepts of a parabola, and each one is usually specific to each situation.

In the case, when you are given the graph, the easiest way to find x-intercepts is to identify points at which parabola intersects the x-axis.

From your graph, parabola intersects x-axis at two points: (-5,0) and (-4,0)

(-5,0) and (-4,0)

Step-by-step explanation:

We know that ,

X-intercept = Points where the graph intersects the x-axis.

From the given graph , the parabola is intersecting the x-axis at two distinct points .

Two points where  parabola is intersecting the x-axis : (-5,0) and (-4,0)

Therefore, the x-intercepts of the parabola = (-5,0) and (-4,0)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

depends on how many days you are talking about

step-by-step explanation: