When 9 is increased by 3x the result is greater than 36. what is the least possible interger value for x?

10

Step-by-step explanation:

"When 9 is increased by 3x"

THis means 9 + 3x

"The result is greater than 36"

We use greater than sign and 36

So we can write:

9 + 3x > 36

SOlving this via equation rules and algebra:

9 + 3x > 36

3x > 36 - 9

3x > 27

x > 27/3

x > 9

This means x is everything greater than 9, which satisfies the equation. So in terms of integers, it can be 10, 11, 12, 13...anything above

We want to find the least possible integer value of x, so it is definitely 10

10

Step-by-step explanation:

First we have to convert the given statement into the expression.

9 is increased by 3x. This means 3x is being added to 9. So the expression will be: 9 + 3x

The result of this is greater than 36. So, the result is:

9 + 3x > 36

We have to find the least possible integer value for x i.e. the smallest integer that would satisfy the above inequality.

Subtracting 9 from both sides of the inequality, we get:

3x > 36 - 9

3x > 27

Dividing both sides by 3, we get:

x > 9

This means x must be greater than 9. So, the integer values that would satisfy this inequality would be: 10, 11, 12, 13,

So, from here we can conclude that the least possible integer value for x would be 10. The answer cannot be 9, as x must be greater than 9 as represented by x > 9.

the answer is su.k.my? ? co.kc

step-by-step explanation:

(3rd option) - c