Na survey of 1227 people, 828 people said they voted in a recent presidential election. voting records show that 65% of eligible voters actually did vote. given that 65% of eligible voters actually did vote. a) find the probability that among 1227 randomly selected voters, at least 828 actually did vote. b) what do the results from part (a) suggest?

0.0344

Step-by-step explanation:

For binomial distribution :-

, where p is the proportion of success in each trial and n is the sample size.

Given : Sample size : n=1227

The proportion of people said they voted in a recent presidential election :p=0.95

Then,

Let X be the binomial variable.

z-score :

For x= 828

Then,  probability that among 1227 randomly selected voters, at least 828 actually did vote is given by :-

Hence,  the probability that among 1227 randomly selected voters, at least 828 actually did vote= 0.0344

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form