10(y+2)-y=2(9y-8) i need to know how to solve it

10(y+2)-y=2(9y-8)

Mutiply the first bracket by 10

Mutiply the second bracket by 2

(10)(y)(10)(2)= 10y+20

(2)(9y)(2)(-8)= 18y-16

10y+20-y= 18y-16

10y-y+20= 18y-16

9y+20= 18y-16

move 18y to the other side

sign changes from +18y to -18y

9y-18y+20= 18y-18y-16

-9y+20= -16

move +20 to the other side

sign changes from +20 to -20

-9y+20-20=-16-20

-9y= -36

divide by -9

-9y/-9= -36/-9

y= 4

y= 4