F. a bag contains 3 red, 4 blue, 3 green, and 5 yellow marbles. what is the probability of
picking two green marbles in a row, without replacing the first marble?

Step-by-step explanation:

you first add up the marbles together. 3 + 4 + 3 +.5 = 15. Then you take the amount of green marbles their are, and make a fraction: 3/15. Then you remove one without putting it back, which is green, so you have 1 less total and one less green marbles, and you turn that into a fraction: 2/14.

First Pick: 3/15 chance of getting green

Second Pick: 2/14 chance of getting green

Then. You divide the first number by the second one.

3 / 15 = 0.2

2 / 14 = 0.142

Then to turn into percentage you move the decimal over two spots and drop the 0 and add a percentage sign:

20%

14.2% (Round Up Percentage) 15%

Which means that:

20% Probabiltiy for first pick

15% Probability for second pick

  I hope this helps. If it is incorrect, comment that, and I will see what U messed up. I hope I helped. :D

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: