25 points-
find the area of the larger sector.
leave your answer in terms of pi.

33 pi

Step-by-step explanation:

Area of the larger sector = Area of the circle - Area of the smaller sector

Area of the circle = (6)^2 pi = 36 pi

Area of the smaller sector = 1/2 × (6)^2 × theta,where theta has to be in radians

30° = pi/6

Area of the smaller sector = 1/2 × 36 × pi/6

= 3 pi

Area of the larger sector = 36 pi - 3 pi

Area = 33 pi

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.