Consider the minitab output shown: paired t-test and ci: x1, x2paired t for x1 - x2 n mean stdev semeanx1 12 74.2430 1.8603 0.5370x2 12 73.4797 1.9040 0.5496difference 12 ? 2.905560 0.83876395% ci for mean difference: (-1.082805, 2.609404)t-test of mean difference = 0 (vs not = 0): t-value = ? , p-value = ? a) fill in the missing values in the output, including a boundon the p-value. can the null hypothesis be rejected at the0.05 level? why? b) is this a one-sided or a two-sided test? c) use the output and the t table to find a 99% two-sided cion the difference in means. d) how can you tell that there is insufficient evidence toreject the null hypothesis just by looking at the computer outputand not making any additional computations?